2y^2-5y=-10

Solution for 2y^2-5y=-10 equation:

Simplifying
2y2 + -5y = -10

Reorder the terms:
-5y + 2y2 = -10

Solving
-5y + 2y2 = -10

Solving for variable 'y'.

Reorder the terms:
10 + -5y + 2y2 = -10 + 10

Combine like terms: -10 + 10 = 0
10 + -5y + 2y2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
5 + -2.5y + y2 = 0

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -2.5y + -5 + y2 = 0 + -5

Reorder the terms:
5 + -5 + -2.5y + y2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -2.5y + y2 = 0 + -5
-2.5y + y2 = 0 + -5

Combine like terms: 0 + -5 = -5
-2.5y + y2 = -5

The y term is -2.5y.  Take half its coefficient (-1.25).
Square it (1.5625) and add it to both sides.

Add '1.5625' to each side of the equation.
-2.5y + 1.5625 + y2 = -5 + 1.5625

Reorder the terms:
1.5625 + -2.5y + y2 = -5 + 1.5625

Combine like terms: -5 + 1.5625 = -3.4375
1.5625 + -2.5y + y2 = -3.4375

Factor a perfect square on the left side:
(y + -1.25)(y + -1.25) = -3.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.